Question

R(0,-3),S(0,5/2) How to solve with distance formula? with steps​

Answer 1

R(0,-3),S(0,5/2) find the length of RS by using the distance formula. (correct question)

Given:

R(0,-3),S(0,5/2)

To  find:

The length of RS.

Solution:

The distance formula to find the length of any line segment with two coordinates.

• $\sqrt{(x2-x1)^{2}+(y2-y1)^{2} }$

we have

R(0,-3),S(0,5/2)

• $\sqrt{(0-0)^{2}+(5/2-(-3))^{2} }$
• $\sqrt{(0-0)^{2}+(5/2+3)^{2} }$
• $\sqrt{(11/2)^{2} }$
• 11/2

The length of RS is 11/2 i.e. 5.5 units.

Answer 2

Answer:

R(0,-3),S(0,5/2) find the length of RS by using the distance formula. (correct question)

Given:

R(0,-3),S(0,5/2)

To  find:

The length of RS.

Solution:

The distance formula to find the length of any line segment with two coordinates.

\sqrt{(x2-x1)^{2}+(y2-y1)^{2} }(x2−x1)2+(y2−y1)2

we have

R(0,-3),S(0,5/2)

\sqrt{(0-0)^{2}+(5/2-(-3))^{2} }(0−0)2+(5/2−(−3))2

\sqrt{(0-0)^{2}+(5/2+3)^{2} }(0−0)2+(5/2+3)2

\sqrt{(11/2)^{2} }(11/2)2

11/2

The length of RS is 11/2 i.e. 5.5 units.