Question

r=1÷3 ;a=9 find t7 ​

Answer 1

T7 = a r^6 = 9 × (1/3)^6 = 1/81

Answer 2

Answer:

$T_{7} = \frac{1}{81}$

Step-by-step explanation:

As per the question,

According to  geometric progression ,

The n-th tern is given by  $=ar^{n-1}$

where,

a = firsts term

r = common difference

n = number of terms

From the given data of question,

a = 9

r = 1/3

We have to find the 7-th term of series

$T_{7} = ar^{6}$

$T_{7} = 9(\frac{1}{3} )^{6}$

$T_{7} = \frac{1}{81}$

Hence, $T_{7} = \frac{1}{81}$.