R=10 ohms and r1 =20 and r2 =40 what is the r3
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Total R = 10 ohms
Since the resistors seems to be connected in parallel
∴ 1/R = 1/r1 + 1/r2 + 1/r3
⇒ 1/10 = 1/20 + 1/40 + 1/r3
[let r3 = x]
⇒ 1/10 =
⇒ = 5x + 40
⇒ 40x = 50x + 400
⇒ -10x = 400
⇒ x = 40 ohms
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