R=10cm. r=6cm, h= 3cm find rolurme
and curred sunfall Area of frustem
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Answer:
VOL.= 615.44 CM³
C.S.A=251.2 CM²
Step-by-step explanation:
GIVEN:R=10 CM
r=6 CM
H=3 CM
NOW,VOL OF FRUSTUM
(πH)/3{R²+r²+(R)(r)}
(3.14×3)/3{10²+6²+(10)(6)}
3.14{136+60}
3.14{196}
615.44 cm³
NOW FOR CURVED SURFACE
L=√(H²)-(R²-r²)
L=5 CM
C.S.A=π(R+r)L
3.14(10+6)5
3.14×16×5
3.14×80
251.2 CM²
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