Question

Р
R
12. PQ is perpendicular to RS
Prove that:
PR2 + QS2 = QR2 + PS2
S
13. In a rhombus ABCD, prove that
AC?+ BD2 - 4BC
D
14. In the adjacent diagram prove that
AC2+CD2 BD? + AB?
B
C С​

Answer 1

Answer:

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Answer 2

Answer:

Ans(12) -Given PQ is perpendicular to RS

Step-by-step explanation:

In ∆PRQ

(PR) ^2=(PQ.)^2+(QR)^2

(PQ)^2=(PR)^2-(QR)^2----------1

In ∆PQS

(PS) ^2=(PQ)^2+(QS)^2

(PQ) ^2=(PS)^2-(QS)^2----------2

From Eqn 1 and 2........

(PR) ^2 +(QS) ^2= (PS) ^2 +(QR) ^2

Hence Proved......