Question

r^2=(r-3)^2+4^2 can you plz solve this

Answer 1

${x}^{2} = {(x - 3)}^{2} + {4}^{2} \\ \\ {x}^{2} = {x}^{2} - 6x + 9 + 16 \\ \\ {x}^{2} - {x}^{2} + 6x = 25 \\ \\ 6x = 25 \\ \\ x = \frac{25}{6}$

Answer 2

${r}^{2} = (r - 3)^{2} - {4}^{2} \\ \\ {r}^{2} = ({r}^{2} - 6r + 9) - 16 \\ {r}^{2} = {r}^{2} - 6r - 7 \\ {r}^{2} = {r}^{2} - 7r + r - 7 \\ {r}^{2} = r(r - 7) + 1(r - 7) \\ {r}^{2} = ( r- 7)( r+ 1) \\ r = \sqrt{(r - 7)(r + 1)}$