Question

r^2p^2z^2+2rpz+1=0
where p not equal to 0
and r not equal to 0

Answer 1

Answer:

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Answer 2

Given,

r^2p^2z^2+2rpz+1=0

p ≠ 0

r ≠ 0

To Find,

Value of rpz=?

Solution,

$r^2p^2z^2+2rpz+1=0$

let rpz =x for convenience. We get,

$x^2 + 2x + 1= 0$

$x^2 + x + x + 1= 0$ (Splitting 2x into x+x )

$x(x+1) +1(x+1) = 0\\(x+1)(x+1) = 0$

Now, x+1 = 0

x = -1

Hence, rpz = -1