r = 3.0t i = - 2.0t² j + 4.0km
where t is in seconds and the cofficients have the proper units for r to be in metres.
(a). Find the v and a of the particle ?
(b). What is the magnitude and direction of velocity of the particle at t = 2.0s
Answers
Answered by
2
Answer:
(a)
v(t)=dr/dt
=3.0i^−4.0tj^
a(t)=dv(t)/dt
=−4.0j^
(b)
v(2)=3.0i^−8.0j^
v(2)=8.54m/s
∠v(2)=tan−1(−8/3)=−69.44∘with x axis
Answered by
1
Answer:
r = 3.0t i = - 2.0t² j + 4.0km
where t is in seconds and the cofficients have the proper units for r to be in metres.
(a). Find the v and a of the particle ?
(b). What is the magnitude and direction of velocity of the particle at t = 2.0s
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