Question

R=30 R=6 are connected in parallel
find Rp​

Answer 1

Explanation:

1/Rp = 1/R1 + 1/R2

1/Rp = (R1 + R2)/R1*R2

Rp = R1 * R2 / R1 + R2

Rp = (30 * 6)/(30 + 6)

= (30 * 6)/36

= 30/6 = 5 ohm

Answer 2

Answer:

5 Ω

Explanation:

Given :

R₁ = 30 Ω

R₂ = 6 Ω

We have to find net resistance when they connected in series!  

We know :

R_p = R₁ R₂ / R₁ + R₂

Putting values here we get :

R_p = 30 × 6 / ( 30 + 6 ) Ω

= > R_p = 30 × 6 / 36 Ω

= >  R_p = 30 / 6 Ω

R_p = 5 Ω

Hence we get required answer!