Question

R
4. PQRS represents a frame which is kept vertically. Over this frame a rod
MN of length 20 cm can slide as
shown. The whole system is
dipped in a soap solution and then
withdrawn. What should be the
mass of the block C which has to
ac
be suspended from the wire in
IC
IS
order to keep it in equilibrium ?
(S. T. of soap solution = 30 x 10-3 N/m; neglect friction]
Ans. 1-22 x 10-3 kg.
Here the force exerted by the S. T. = 2TL
For equilibrium of the rod, Mg = 2TL
Where M is the mass of the block C.
2TL 2 x 30 x 10-3 x 0.2
.. M=
= 1.22 x 10-3 kg
9.8​

Answer 1

Answer:

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