R=50000 , n=2 2/3 , R=6%
Find the compound intrest using formula
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Answered by
0
P = 50000
t =
years
R = 6%
![A = P[1+ \frac{r}{100} ]^{t}\\ \\ \Rightarrow A= 50000[1+ \frac{6}{100} ]^{8/3}\\ \\ \Rightarrow A= 50000[1+ 0.06 ]^{8/3}\\ \\ \Rightarrow A= 50000[1.06 ]^{8/3}\\ \\ \Rightarrow A=Rs.\ 58405.3 A = P[1+ \frac{r}{100} ]^{t}\\ \\ \Rightarrow A= 50000[1+ \frac{6}{100} ]^{8/3}\\ \\ \Rightarrow A= 50000[1+ 0.06 ]^{8/3}\\ \\ \Rightarrow A= 50000[1.06 ]^{8/3}\\ \\ \Rightarrow A=Rs.\ 58405.3](https://tex.z-dn.net/?f=A+%3D+P%5B1%2B+%5Cfrac%7Br%7D%7B100%7D+%5D%5E%7Bt%7D%5C%5C+%5C%5C+%5CRightarrow+A%3D+50000%5B1%2B+%5Cfrac%7B6%7D%7B100%7D+%5D%5E%7B8%2F3%7D%5C%5C+%5C%5C+%5CRightarrow+A%3D+50000%5B1%2B+0.06+%5D%5E%7B8%2F3%7D%5C%5C+%5C%5C+%5CRightarrow+A%3D+50000%5B1.06+%5D%5E%7B8%2F3%7D%5C%5C+%5C%5C+%5CRightarrow+A%3DRs.%5C+58405.3)
So compound Interest, CI = A - P = 58405.3 - 50000 = Rs. 8405.3
t =
R = 6%
So compound Interest, CI = A - P = 58405.3 - 50000 = Rs. 8405.3
manasvini:
t= 2 2/3 yrs
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