R.60000 is invested at 7% interest rate p.a. Find the interest at the end of 3 years.
Answers
Answered by
2
Answer:
i. P = ₹ 60,000
Rate = 12% per annum = 6% per half year
n = 6 months = 1 half year
\text { Amount, } A \quad=P\left(1+\frac{R}{100}\right)^{n}
=₹ \left[60000\left(1+\frac{6}{100}\right)^{1}\right]
=₹ \left[60000\left(1+\frac{3}{50}\right)^{1}\right]
= ₹ \left[60000 \times \frac{53}{50}\right]
= ₹ 63600
ii. There are 2 half years in 1 year.
n = 2
\text { Amount, } A \quad=P\left(1+\frac{R}{100}\right)^{n}
=₹ \left[60000\left(1+\frac{6}{100}\right)^{2}\right]
=₹ \left[60000\left(1+\frac{3}{50}\right)^{2}\right]
= ₹ \left[60000 \times \frac{53}{50} \times \frac{53}{50}\right]
= ₹ 67416
Hope this helps you Bro:))
Answered by
0
Answer:
rs, 60000
Step-by-step explanation:
7% 3 year
pa is 3
intrest 60000
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