Math, asked by czinteroomcard, 20 hours ago

R.60000 is invested at 7% interest rate p.a. Find the interest at the end of 3 years.​

Answers

Answered by XxitzaBrainlyStarxX
2

Answer:

i. P = ₹ 60,000

Rate = 12% per annum = 6% per half year

n = 6 months = 1 half year

\text { Amount, } A \quad=P\left(1+\frac{R}{100}\right)^{n}

=₹ \left[60000\left(1+\frac{6}{100}\right)^{1}\right]

=₹ \left[60000\left(1+\frac{3}{50}\right)^{1}\right]

= ₹ \left[60000 \times \frac{53}{50}\right]

= ₹ 63600

ii. There are 2 half years in 1 year.

n = 2

\text { Amount, } A \quad=P\left(1+\frac{R}{100}\right)^{n}

=₹ \left[60000\left(1+\frac{6}{100}\right)^{2}\right]

=₹ \left[60000\left(1+\frac{3}{50}\right)^{2}\right]

= ₹ \left[60000 \times \frac{53}{50} \times \frac{53}{50}\right]

= ₹ 67416

Hope this helps you Bro:))

Answered by dp283550
0

Answer:

rs, 60000

Step-by-step explanation:

7% 3 year

pa is 3

intrest 60000

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