Question

R
7. In the given figure, PQ, PR and BC are the tangents to the circle. BC
the circle at X. If PQ=7 cm, then the perimeter of APBC is,
A) 9 cm
B) 12 cm
C) 14 cm
D) 21 cm

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Answer 1

Answer:

Step-by-step explanation:

Correct question :-

In the given figure , PQ, PR and BC are the

tangents to the circle. BC touches the circle

at X. If PQ = 7cm , then the perimeter ΔPBC.

Solution :-

We know that

The lengths of tangents drawn from an external point of a circle are equal

CR and XR are two tangents drawn from an external point C

⇒ CR = XC

BQ and XB are two tangents drawn from an external point B

⇒ BQ = XB

PR and PQ are two tangents drawn from an external point P

⇒ PR = PQ = 7 cm

Perimeter of ΔPBC = PC + PB + BC

From figure,

= PC + PB + (BX + CX)

= PC + CX + BX + PB

= (PC + CR) + (BQ + PB)

[ Because CX = CR, BQ = BX ]

= PR + PQ

= 7 + 7

[ Because PR = PQ = 7 CM ]

= 14 cm

Therefore, the perimeter of ΔPBC is 14 cm.