Question

=
R= 98
7
9.9 cm
Thus, thickness of the pipe = 9.9 - 9 = 0.9 cm
91. What length of tarpaulin 3 m wide will be
required to make conical tent of height 8 m
and base radius 6 m ? Assume that the extra
length of material that will be required for
stitching margins and wastage in cutting is
approximately 20 cm. (use n = 3.14)
Sol. Given, radius of the base (r) = 6 m
Haight of the cone (h) 8 m​

Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.