R
AC meets CD and AB at Cand Aresp. CE and AE are the bisectors of
that 21+ Z2 = 90°. Prove that AB||CD.
2
pe B
AC=PQ and CP=BQ. Prove that Pis mid point of the line segment AB.
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HdfsggCalculate the degree of dissociation of 0..02...Calculate the degree of dissociation of 0..02...Calculate the degree of dissociation of 0..02...665/*655+//==2/'!*6'-55,*5+//2-*596/'/5
BhoomikaArora:
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