R
AIIMS 2012
The value of current i for the given circuit is --
(2) 5 A
(1) 10 A
(3) 2.5 A (4) 20 A
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Req is 5/2 ohm and from ohm's rule V=i×R then I is 10 A
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Answer:
10 A
Explanation:
no current will flow through the 5 ohms in the middle as the Wheatstone bridge is balanced.
two 5 ohms in the top will have an effective resistance of 10 ohms
two 5 ohms in the bottom will have an effective resistance of 10 ohms
these two are in parallel so effective resistance will be 5 ohms
this 5 ohms and the 5 ohms at the lower part are parallel so effective resistance is 5/2 ohms
I = V/R=25/2.5=10 A
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