Question

r cosA =2/√3 and r sinA=2 then r=?

Answer 1

Answer:

Step-by-step explanation:

rcosA=2/√3

(rcosA)^2 =(2/√3)^2

r^2 cos^2 A =4/3

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rsinA =2

(rsinA)^2 =2^2

r^2 sin^2 A=4

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r^2 cos^2 A + r^2 sin^2 A =4/3 + 4 = 16/3

r^2 (cos^2 A + sin^2 A)=16/3

r^2(1) =16/3

r^2 =16/3

r=√(16/3)

r=4/√3

r=(4√3)/3

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