R.F. of cuberoot a + cuberoot b
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Answered by
7
a+b = (a^1/3 + b^1/3)(a^2/3 - a^1/3b^1/3 + b^ 2/3) So, (a^1/3 + b^1/3) = (a + b)/(a^2/3 - a^1/ 3b^1/3 + b^2/3)
Answered by
0
Answer:
3√a²-3√ab+3√b²
explanation
use a³+b³ = (a+b) (a²-ab+b²)
therfore a+b= (³√a+³√b) (³√a²-3√ab+3√b²)
therefore when second bracket is multiplied by first answer is ration so it is rf
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