Question

R.
g) ABCD is a parallelogram and P is any point on CD. If AADP = 10 sq.cm and
AACP = 15 sq. cm, find the area of AABP.​

Answer 1

$\huge\fcolorbox{black}{teal}{Solution:-}$

✏ Correct Question :-

★ ABCD is a parallelogram, P is any point on CD. If Ar. (ADP) = 10cm² and Ar. (ACP) = 15cm². Find the Ar. (ABP).

✏ Answer :-

★ Area of ∆ABP = 25 cm².

✏ Step-by-step explanation :-

★ Given :-

• Ar. (ADP) = 10 cm²

• Ar. (ACP) = 15 cm²

★ To Find :-

• Ar. (ABP)

★ Rationale :-

• Area of ∆ACD = (10 + 15) cm²

⇒Ar. (∆ACD) = 25 cm²

Now,

As we know, in a parallelogram, the opposite sides are equal.

∴ CD = AB

Also,

AB || CD

We know that,

Triangles lying on the same base and between the same ||lels have the same area.

⇒Ar. (∆ABP) = Ar. (∆ACD)

⇒ Area of ∆ABP = 25 cm².

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I hope this helps! :)