r. If x} +1 x² – 3x+2 then k= 7x-5 =(kx – 5)+ (x-1)(x-2) 2) 7 1)5 3)1
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By remainder theorem, when f(x) is divided by (x−2)
x−2=0,⇒x=2
the remainder =f(2)
=2(2)3+3(2)2−k(2)+5
=16+12−2k+5
=33−2k
According to question
33−2k=7
⇒2k=26
⇒k=13
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