Question

R is horizontal range and H is max height for a give projectile, angle of projection is tan inverse (4H/R), to find the angle of projection, what should be the steps followed

2 points

find angle of projection by starting with finding all x and y components of motion and start solving by finding time of flight

find angle of projection by starting with finding all x and y components of motion and use equation of trajectory

find angle of projection by defining range and max height in terms of x and y components of initial velocity using standard results of H and R, assuming angle to be theta, and then dividing the two results

find angle of projection by using the fact that max horizontal range of a projectile is at 45 degrees​

Answer 1

Answer:

ᴍᴀxɪᴍᴜᴍ ʜᴇɪɢʜᴛ, ʜ = 2ɢᴜ2ꜱɪɴ2θ-----(ɪ)

ʜᴏʀɪᴢᴏɴᴛᴀʟ ʀᴀɴɢᴇ, ʀ = ɢᴜ2ꜱɪɴ2θ = ɢ2ᴜ2ꜱɪɴθᴄᴏꜱθ------(ɪɪ)

ᴅɪᴠɪᴅᴇ (ɪ) ʙy (ɪɪ), ᴡᴇ ɢᴇᴛ

ʀʜ=4ᴛᴀɴθ ᴏʀ ᴛᴀɴθ=4ʜ/ʀ ᴏʀ θ=ᴛᴀɴ−1(4ʜ/ʀ)