R-OH+CH2N2. Leaving group in this reaction is - (A)CH3, (B)R, (C)N2, (D)CH2.
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I think it's (B) R.................
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Answer: The leaving group in the given reaction ROH + CH2NH2 is N2.
Explanation:
This is the Fischer–Speier esterification reaction. In this reaction, an alcohol (here, R-OH) where R is any alkyl group reacts with ammino group (here, CH2NH2) causes diazotization.
A compound with sweet fragrance is formed as a product which is known the ester.
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