Physics, asked by bhosaleanuj723, 11 months ago

R = P2 + Q2 + 2PQ cos​

Answers

Answered by johnkumarrr4
18

Answer:

Explanation:

Let  two vector  P and Q have same initial point and they do not meet each other .Both vector have different direction and angle between the vector is \Theta .Let a vector R which join the vector P and Q.

We can find out the value of R  in terms of P ,Q and \Theta.

R^{2}=P^{2}+Q^{2}+2PQcos\Theta

where R is the resultant vector

\sqrt{R^{2}}=\sqrt{P^{2}+Q^{2}+2PQcos\Theta

R=\sqrt{P^{2}+Q^{2}+2PQcos\Theta

here R defined only magnitude

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