Question

R(R+1),(R+2),.......R+n in series combination calculate the equal resistance .​

Answer 1

Explanation:

To solve this question we can use arithmetic progressions

Here

a=R

d=1

We know that

Sum of n terms in an ap is

• n/2*(2a+(n-1)d)

Hence

If resistors are connected in series then

• n/2*(2R+(n-1)1)
• n/2*(2R+n-1)

Hope you understood the solution

if you don't know arithmetic progressions then first refer the chapter

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