R + r = 2R/√3 , solve for R/r
Light1729:
Solid state?
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2
R+r = 2R/√3
or,2R =R√3+r√3
or,2R - R√3 =r√3
or,R(2-√3) =r√3
or,R/r = √3/(2-√3)
= √3*√3/2-√3*√3
= 3 / 2-3
= 3/-1
so the ans is R/r = 3/-1
or,2R =R√3+r√3
or,2R - R√3 =r√3
or,R(2-√3) =r√3
or,R/r = √3/(2-√3)
= √3*√3/2-√3*√3
= 3 / 2-3
= 3/-1
so the ans is R/r = 3/-1
Answered by
0
Hi ,
R + r = 2R/√3
r = 2R/√3 - R
r = R( 2 /√3 - 1 )
r /R = ( 2 - √3 ) / √3
R/r = √3 / ( 2 - √3 )
R/r = √3( 2 + √3 ) / [ (2 - √3 )(2 + √3 )
R / r = √3 ( 2 + √3 ) / [ 4 - 3 ]
R/r = √3 ( 2 + √3 )
I hope this helps you.
:)
R + r = 2R/√3
r = 2R/√3 - R
r = R( 2 /√3 - 1 )
r /R = ( 2 - √3 ) / √3
R/r = √3 / ( 2 - √3 )
R/r = √3( 2 + √3 ) / [ (2 - √3 )(2 + √3 )
R / r = √3 ( 2 + √3 ) / [ 4 - 3 ]
R/r = √3 ( 2 + √3 )
I hope this helps you.
:)
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