Question

r s aggarwal chapter 4 ex 4b class 10​

Answer 1

Step-by-step explanation:

4x²+4[3x+3=0

(2x)²+2 into x[3= -3

Adding(√3)² to both side s,

(2x)²+2multiply 2xmultiply √3+(√3)²= -3+(√3)²

(2x+√3)²=-3+√3=0

2x+√3=0=2x=√3.

Answer 2

Answer:

The roots of the equation are ${2\sqrt{3} /3}$ and ${-4\sqrt{3}}$.

Step-by-step explanation:

Given:

The given equation is $\sqrt{3} x^{2} +10x-8\sqrt{3}=0$.

To find:

The roots of the given equation $\sqrt{3} x^{2} +10x-8\sqrt{3}=0$.

Solution:

Comparing it with $ax^{2} +bx+c=0$

we get, a =$\sqrt{3}$, b=10 and c=$-8\sqrt{3}$.

∴D= $b^{2} -4ac$ =$10^{2} -4\sqrt{3}*(-8\sqrt{3})$

    = 100+96

    =196>0.

So, the equation has real roots, given by

⇒α = $(-b+\sqrt{D})/2a$

⇒β = $(-b-\sqrt{D})/2a$

Hence, the roots of the equation are ${2\sqrt{3} /3}$ and ${-4\sqrt{3}}$.

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