Math, asked by dramya1994, 23 days ago

R started a business by investing Rs.10,000. After 6 months S joined with him by investing Rs. 16,000. At the end of 3 years they gained Rs.49000 then the share of R is:​

Answers

Answered by Sauron
49

Step-by-step explanation:

  • Amount invested by R = Rs. 10,000
  • After 6 months
  • Amount invested by S = Rs. 16,000
  • At the end of 3 years they gained Rs. 49,000

Share of R = ??

Solution :

• Total Amount invested by R =

= 10,000 × 36 = 3,60,000

• Total Amount invested by S =

= 16,000 × 30 = 4,80,000

Ratio =

  • R : S
  • 3,60,000 : 4,80,000
  • 36 : 48 = 3 : 4

They gained Rs. 49,000

Share of R =

= (3/7) × 49,000

= 21,000

Share of R = Rs. 21,000

Therefore, the share of R is Rs. 21,000

Answered by BrainlyButtercup96
61

Answer

Given:-

R started a business by investing Rs.10,000. After 6 month S joined with him by investing Rs.16,000. At the end of 3 years they gained Rs.49,000.

As we know that,

Profit = Investment×Time Period

Now,

  • The time period of R is :- 3×12=36 month
  • The time period of S is :- 3×12= 36-6 = 30 months.

So, the profit of R will be :

P = 10,000×36 = Rs.3,60,000

Now, the profit of S will be :

P = 16,000×30 = Rs.4,80,000

Therefore, the share of R (Sr) will be:

Sr = \frac{3,60,000}{3,60,000+4,80,000}\times 49000

Sr \:  =\frac{3,60,000}{8,40,000} \times 49000

Sr =  \frac{36}{84}  \times 49000

Sr =  \frac{3}{7}  \times 49000

Sr = 3 \times 7000

Sr = 21000

Therefore the share of R will be Rs.21,000.

Similar questions