Question

R the cell zn(s)zn2+(aq)mx+(aq)m(s) different half cells and their standard electrod

Answer 1

Answer:

As we know that

$E^{0} cell=E_{oxidation} ^{0} +E_{reduction} ^{0}$

$=E^{0} _{Zn(s)Zn^{2+} } +E_{Al^{+3}/Au(s) } ^{0}$

=0.76+1.40V

=2.16

$E^{0}$ cell is maximum with $E^{0} Au^{+3} /Au(s)$ among others in the cell reaction electrons transferred quantity doesn't matter

so correct option is $Au^{3+} /Au$