Question

R (x) = 5x –5 Put x = 1, R(1) = _______ ∴ R(1) = _______ S(x) = x2 –2x Put x = 0, S (0) = (0)2 – 2(0) S (0) = 0 – 0 ∴ S (0) = 0 S(x) = x2 –2x Put x = 1, S (1) = _______ S (1) = _______ ∴ S (1) = _______ S(x) = x2 –2x Put x = 2, S (2) = _______ S (2) = _______ ∴ S (2) = _______ P(x) = x – 1 Put P(x) = 0, x – 1 = 0 ∴x = 1 Q(x) = 3x – 1 Put Q(x) = 0, 3x – 1 = 0 3x = 1 ∴ x = R(x) = x – 5 _______________ _______________ _______________ P(x) = 5x – 1 _______________ _______________ _______________ _______________ Q(x) = 3x _______________ _______________ _______________ _______________ ​

Answer 1

Answer:

zero

Step-by-step explanation:

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