R1 = 10 ohm,R2=40ohm,R3=30ohm,R4=20ohm,R5=60ohm and a 12V battery is connected to the arrangement.Calculate (a) total resistance in the circuit,(b) total current in the circuit,(c) current flowing through R1 and R2
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Answer:
R1=10 ohm; R2=40 ohm; R3=30 ohm; R4=20 ohm;R5=60 ohm.
V=12V
R=?
I=?
I1 and I2=?
Explanation:
assuming the arrangement is in series(because the type of arrangement has not been mentioned here in this question.)
IN SERIES,
(a) Total Resistance=R1 + R2 + R3 + R4 + R5
=10ohm + 40 ohm + 30 ohm +20 ohm + 60 ohm
=160 ohm.
(b) Total Current in the circuit=?
I=V/R
=12/160
=0.075 A.
(c) Current flowing through R1 and R2?
*Same current flows through all the resistors connected in series.
i.e.,
R1 = 0.075 A & R2 = 0.075 A.
this is the answer for the question.
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