Science, asked by wwwhirakjyotimahanta, 6 months ago

R1 = 10 ohm,R2=40ohm,R3=30ohm,R4=20ohm,R5=60ohm and a 12V battery is connected to the arrangement.Calculate (a) total resistance in the circuit,(b) total current in the circuit,(c) current flowing through R1 and R2​

Answers

Answered by sumimolsunil123
0

Answer:

R1=10 ohm; R2=40 ohm; R3=30 ohm; R4=20 ohm;R5=60 ohm.

V=12V

R=?

I=?

I1 and I2=?

Explanation:

assuming the arrangement is in series(because the type of arrangement has not been mentioned here in this question.)

IN SERIES,

(a) Total Resistance=R1 + R2 + R3 + R4 + R5

=10ohm + 40 ohm + 30 ohm +20 ohm + 60 ohm

=160 ohm.

(b) Total Current in the circuit=?

I=V/R

=12/160

=0.075 A.

(c) Current flowing through R1 and R2?

*Same current flows through all the resistors connected in series.

i.e.,

R1 = 0.075 A  &  R2 = 0.075 A.

this is the answer for the question.

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