R1=12ohm, R2=22ohm,R3=24ohm,R=?
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Answer:
R = R1+R2+R3 when connected in series = 12+22+24 = 58 ohms
R = 1/R1+1/R2+1/R3 if connected in parallel = 1/12+1/22+1/24 = 0.17045 ohms
Explanation:
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