Question

R1=1ohm,R2=3ohm,R3=5ohm and R4=7ohm connected in parallel . total current =23A.then V11,12=?​

Answer 1

Explanation:

let the equivalent resistant be ' R '

So,

$\frac{1}{r} = \frac{1}{r1} + \frac{1}{r2} + \frac{1}{r3}$

$= > \frac{1}{r} = \frac{1}{3} + \frac{1}{5} + \frac{1}{7}$

$= > \frac{1}{r} = \frac{35 + 21 + 15}{105}$

$= > \frac{1}{r} = \frac{71}{105}$

$so \: \: \: r = \frac{105}{71}$

Now total current , i = 23A

Voltage , v = ?

According to ohm's law

$v \: = \: ir$

$= > v = 23 \times \frac{105}{71}$

$= > v = \frac{2415}{71}$

$= > v = 34 \frac{1}{71} volt$

$so \: \: v = 34.01volt$

Answer 2

Answer:

Total resistance=6/11

Explanation:

parallel =1/Rp=1/R1+1/R2+1/R3

1/Rp=1/1+1/2+1/3

1/Rp=(6+3+2)/6

Rp = 6/11

I hope you will understand and this answer may be help you.