Physics, asked by ajsdevanesan, 11 months ago

R1 =6±0.3 kΩ
R2=10±0.2kΩ
The % error in the equivalent resistance when they are connected in parallel is

Answers

Answered by GMgoutham

5

Explanation:

0.3/6*100=5%

0.2/10*100=2%

total % error=7%

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