R1, = 6 Ω, R2 = R3 = 2 Ω, and voltage = 14 volt, determine the electric current in circuit as shown in figure below.
Answers
2 amperes.
Given that, R₁ = 6 Ω
R₂ = R₃ = 2 Ω
Here R₂ and R₃ are connected parallel to each other.
Equivalent resistance ( parallel ) = 1/R₁ + 1/R₂
Equivalent resistance across R₂ and R₃
= 1/2 + 1/2
= 2/2 = 1
R₁ is connected in series to the combined resistor R₂ and R₃.
Equivalent resistance ( series ) = R₁ + R₂
Equivalent resistance across the circuit
= 6 Ω + 1Ω
= 7Ω
Electric current = Voltage / Resistance
Electric current through the circuit
= 14 V / 7 Ω
= 2 Ampere
Electric current flowing through given circuit is 2 amperes.
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