Physics, asked by kkarnik5, 11 months ago

R1 and R2 are two resistors in the circuit connected in parallel. If R = 2R2, and the resultant
resistance of this circuit is 2 ohms then determine the correct value of R1
(A) 6 ohms
(B) 3 ohms
(C)1/6 ohms
(D)1/3 ohms​

Answers

Answered by anjali30703
7

Answer:

6 ohm is the answer......

Attachments:
Answered by srirajnambiar
0

Answer:

R1 and R2 are two resistors in the circuit connected in parallel. If R = 2R2, and the resultant resistance of this circuit is 2 ohms then determine the correct value of R1

(A) 6 ohms

(B) 3 ohms

(C)1/6 ohms

(D)1/3 ohms​

Answer : (A) 6ohms

Explanation:

When two nodes share terminal connections, resistors are said to be in parallel. The lowest parallel resistor is larger than the comparable overall resistance.

Resistance in parallel formula

\frac{1}{R}  =  \frac{1}{R1 }  + \frac{1}{R2}

R = \frac{R1 R2}{R1 + R2}

Given R1 = 2 R2

By putting the value in the formula

R = \frac{2R2 X R2}{2R2 + R2}

= R = \frac{2R2^{2} }{3R2}

By cancelling R2 by  R2

R = \frac{2R2}{3}

The resistance of this circuit is given = 2 ohms

hence, the value of R is 2 ohm

2 =  \frac{2R2}{3}

6= 2R2

here, R2 = 3 ohm

by putting the value of R2 in the given information

R1 = 2 R2

R1 = 2 X 3 ohm

R1 = 6 ohms ( Answer)

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