R1 and R2 be the resistance of the filament of 40 W and 60 W respectively operating 220 V, then R1 is ____________ than R2.
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Power of bulb is inversely proportional to the resistance of filament wire of bulb hence,
P2P1=R1R2
100200=R1R2
⇒R1R2=2
Hence, R2=2R1
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