r1 r2/r1+r2=6/5,,,then r1 and r2 =?
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r1 r2/r1+r2=6/5...then r1 and r2=r
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this equation can't be solved directly.
in case a relation will be
![r1 = 6(r1 + r2) \div 5r2 r1 = 6(r1 + r2) \div 5r2](https://tex.z-dn.net/?f=r1+%3D+6%28r1+%2B+r2%29+%5Cdiv+5r2)
in case a relation will be
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