Physics, asked by shivanjalisodhu, 1 month ago

R116.)
PÁo simple pendulum A and B of length 1.69 m and 1.44 m start swinging at the same
time from a location where acceleration due to gravity is 10 ms2.
Answer the following questions
How many vibrations pendulum A will complete when it will be out of phase
with B?
(a) 4
(b) 5
(C) 6
(d) 8
2 2/
After how much time, the two pendulums will be out of phase?
(a) 5.5 s
(b) 10,0 s
(c) 12.6 s
(d) 15.5 s
5.
After how much time, the two pendulums will be in phase again?
(a) 11.0 s
(b) 20.0 s
(C) 25.2 s
(d) 31.0 s
What will be the approximate gain or loss of time by pendulum A in day with
respect to second's pendulum?
(a) 6 hours
(b) 7 hours
(C) 8 hours
(d) 9 hours
Section C
All questions are compulsory. In case of internal choices, attempt anyone
Whird sitting on the floor of a wire core and the case is in the band of how the bird​

Answers

Answered by YASHMATHIYA
2

Answer:

1)4

2)12.6 s

3)20.0 s

4)8 hours

Explanation:

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Answered by amitnrw
1

Given : Two simple pendulum A and B of length 1.69 m and 1.44 m start swinging at the same

time from a location where acceleration due to gravity is 10 m/s²

To Find : How many vibrations pendulum A will complete when it will be out of phase with B?

After how much time, the two pendulums will be out of phase?

After how much time, the two pendulums will be in phase again

.What will be the approximate gain or loss of time by pendulum A in day with respect to second's pendulum

Solution:

T = 2π √L/g

=> T = 2π √1.69/10  =  2.583  sec

  T = 2π √1.44/10  =    2.384  sec

 

2.384 *  (n + 1) = 2.583 * n

=>  n  = 12

Hence after 12   complete rounds of  2.583 pendulum A

 or 13 complete rounds of   2.384  pendulum B

they will be in phase again

2.583 * 12 = 2.384 * 13 = 31  

=> 31 sec    

Hence they will be out of phase in 31/2  = 15.5 secs  and after  6  rounds of pendulum A

approximate gain or loss of time by pendulum A in day with

respect to second's pendulum

second's pendulum  time period = 2 secs

Pendulum A  losses 2.583 -  2  = 0.583  sec for every  2 secs

Hence  (0.583/ 2  ) * 24 =   7  hrs

Hence  approximate  loss of time by pendulum A in day with  

respect to second's pendulum

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