Question

R2 1.37 g cuo was reduced by hydrogen and 1.098g
cu was obtained in another experment, 1.178g
Cu was dissolved
in nitric acid
and the
resulting copper nitrate was converted into CUO
The weight of cuo formed was 1.476g

show that the law of constant
composition is used


10
T7​

Answer 1

Explanation:

First experiment

copper left = 1.098 g

oxygen % = 1.375 - 1.098 == 0.277 g

% of oxygen in cuo = (0.277) (100%) 1.375

== 20.15%

second experiment

cooper taken = 1.179 g

copper oxide formation = 1.46g

oxygen % = 1.479 -- 1.179

== 0.297g

% of oxygen in cuo = (0.297) (100%)

== 1.476 = 20.12%

% of oxygen is approximately so, the law of copmosition is illustrated

i hope it will help u bcoz i also stuied it