रिफॉर्म्स बैलेंस शीट स्टोन इन्वेस्टमेंट सबस्टेशन दिसावर रूपीस 3310 न्यू पार्टनरशिप डीड मार्केट वैल्यू प्लेसमेंट एजेंसी बुक वैल्यू ऑफ द अमाउंट ऑफ इन्वेस्टमेंट लोकेशन इज अ विल बी डिस्ट्रीब्यूटर टर्न ऑफ ओल्ड पार्टनर्स
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Explanation:
A cording to Question, only one statement is applicable. The question is :-
Correct Question:-
The perimeter of the square field is 4x+8. Find the area of its diagonal.
Concept:-
Now, here we need to know that:-
\sf{Area \ of \ Square = a^2}
\sf{Perimeter \ of \ Square = 4a}
Here, a is the side.
So, first, in this question we will find the culprit of the question, which is x.
\sf{4x + 8 = Perimeter}
\sf{4x + 8 = 4a}
Now, we have found the x with respect to a which is the side.
\sf{a = \dfrac{4(x + 2)}{4}}
\sf{a = x + 2}
So, answer is
\sqrt{2}x+2 \sqrt{2}
\sf{Diagonal \ of \ Square = (x+2) \times \sqrt{2}}
\sf{Diagonal \ of \ Square = Side \times \sqrt{2}}
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