राइट इक्वेशन फॉर थे रिएक्शन आफ कैलशियम एंड पोटैशियम विद वॉटर
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A stone is dropped from the top of a 40 m(height) high tower.
Time(t) = 2 sec.
Initial Velocity(u) = 0
Gravitational Acceleration(g) = 9.8 m/s²
Find the speed with which the stone strikes the ground.
According to the First Condition :-
Speed After 2 Seconds.
Now, Put the Value in this Formula :-
Therefore,
The Speed of stone after 2 second will be 19.6 m/s.
∴We know that :-
Therefore,
Speed with which the stone strikes the ground is 28 m/s.
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