रैखिक समीकरण युग्म 2x +3y = 46 तथा 3x+5y = 74 का हल
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Answer:
8,10.
Step-by-step explanation:
2x+3y=46.....(1)
3x+5y=74.....(2)
multiply equation (1)and(2) by 3 and 2 respectively.
thus we get,
3(2x+3y=46)
6x+9y=138.....(3)
2(3x+5y=74)
6x+10y=148...(4)
thus subtracting equation (3)and(4) we get,
y=10
now, substitute y=1 in eq(1)
2x+3y=46
2x+3(10)=46
2x+30=46
2x=46-30
2x=16
x=16/2
x=8
thus x= 8,y=10
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