Question

रिमाइंडर रन 2 एक्स धर्मेंद्र ग्रैंड 2 एक्स क्यूब प्लस 5 एक्स स्क्वेयर माइनस एक्स प्लस टू इज डिवाइडेड बाय टू ​

Answer 1

Answer:

TO DETERMINE

The remainder when x³ - 2x² + x + 1 is divided by x - 1

EVALUATION

Let

\sf{f(x) = {x}^{3} - 2 {x}^{2} + x + 1 }f(x)=x

3

−2x

2

+x+1

g(x) = x - 1

For Zero of the polynomial g(x) we have

g(x) = 0

\implies \sf{x - 1 = 0}⟹x−1=0

\implies \sf{x = 1}⟹x=1

Hence by the Remainder Theorem the required remainder when x³ - 2x² + x + 1 is divided by x - 1 is

= f(1)

\sf{ = {(1)}^{3} - 2 \times {(1)}^{2} + 1 + 1 }=(1)

3

−2×(1)

2

+1+1

\sf{ = 1 - 2 + 1 + 1}=1−2+1+1

= 1=1

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