रूट टू एक्स स्क्वायर प्लस 3 एक्स प्लस रूट 2
Answers
Answer:
Answer:
First term = 1
Common difference = 6
Given statements about the terms of an AP:
9th term = 7 × 2nd Term
9th term = 7 × 2nd Term12th term = 5 × 3rd term + 2
We have to find the following:
First term, a
Common difference, d
The standard form of an AP is:
a , a + d, a + 2d , a + 3d, ... , a + (n - 1)d
Where,
a = first term of AP
d = common difference of AP
So, According to the formula,
aₙ = a + (n - 1)d
We have 9th term and 2nd term as a + 8d and a + d respectively. So According to the statement given,
⇒ 9th term = 7 × 2nd term
⇒ a + 8d = 7 (a + d)
⇒ a + 8d = 7a + 7d
⇒ 7a - a + 7d - 8d = 0
⇒ 6a - d = 0 ...(i)
Similarly, According to the second statement, we have
⇒ 12th term = ( 5 × 3rd term ) + 2
⇒ a + 11d = { 5(a + 2d) } + 2
⇒ a + 11d = 5a + 10d + 2
⇒ 5a - a + 10d - 11d = -2
⇒ 4a - d = -2 ...(ii)
Subtract eq.(ii) from eq.(i), we get
⇒ 6a - d - (4a - d) = 0 - (-2)
⇒ 6a - d - 4a + d = 2
⇒ 6a - 4a = 2
⇒ 2a = 2
⇒ a = 1
We found the first term to be 1, Hence substitute the value of a in eq.(i), we get
⇒ 6a - d = 0
⇒ 6(1) - d = 0
⇒ 6 - d = 0
⇒ d = 6