Question

race car accelerates uniformly from 18.5m/ s to 46.1 metre per second and 2. 47s. Determine the acceleration of the car and the distance travelled.

Answer 1

Hi here is your answer
vi = 18.5 
vf = 46.1 
t = 2.47
d = ??
a = ??
Formula: a = (Delta v)/t

a = (46.1 m/s - 18.5 m/s)/(2.47 s)

a = 11.2 m/s2

d = vi*t + 0.5*a*t2

d = (18.5 m/s)*(2.47 s)+ 0.5*(11.2 m/s2)*(2.47 s)2



d = 79.8 m

Answer 2

Hi here is your answer

vi = 18.5 

vf = 46.1 

t = 2.47

d = ??

a = ??

Formula: a = (Delta v)/t

a = (46.1 m/s - 18.5 m/s)/(2.47 s)

a = 11.2 m/s2

d = vi*t + 0.5*a*t2

d = (18.5 m/s)*(2.47 s)+ 0.5*(11.2 m/s2)*(2.47 s)2

d = 79.