Question

racemirastion occur in sn1 why?

Answer 1

In SN1 reaction there is formation of carbocation intermediate in rate determining first step. So the nucleophile can attack from any side to carbocation.

Answer 2

$<b>____________♦♦♥♦♦____________$

$\huge\mathfrak\purple{\:\:\:\:\:\:\:\:hello\:\:\:mate}$

$<b>____________♦♦♥♦♦____________$
$\tt{\pink{\huge{here\:is\:your\:answer}}}$
$<b>____________♦♦♥♦♦____________$

$\mathbb{\red{\huge{\:\:\:\:\:SN\:2}}}$


( for mechanism of sn2 see attached file 1)

♦♦♦• Reaction is:

Stereospecific (Walden Inversion of configuration)

Concerted - all bonds form and break at same time

Bimolecular - rate depends on concentration of both nucleophile and substrate

♦♦♦• Substrate:

Best if primary (one substituent on carbon bearing leaving group)

works if secondary, fails if tertiary

♦♦♦• Nucleophile:

Best if more reactive (i.e. more anionic or more basic)

♦♦♦• Leaving Group: Best if more stable (i.e. can support negative charge well):

TsO- (very good) > I- > Br- > Cl- > F- (poor)

RF , ROH , ROR , RNH2


♦♦♦• Solvent:

Polar Aprotic (i.e. no OH) is best.

For example dimethylsulfoxide ( CH3 ( HCON(CH3)2 ), acetonitrile ( CH3

Protic solvents (e.g. H2 but can be used in some case are NEVER Substrates for SN2 reactions

Leaving Groups on double-bonded carbons are never replaced by SN2 reactions SOCH3 ), dimethylformamide CN ). O or ROH) deactivate nucleophile by hydrogen bonding


$\mathbb{\red{\huge{\:\:\:\:\:SN\:1}}}$


( for mechanism of sn1 see attached file 2)

♦♦♦• Reaction is:

Non-stereospecific (attack by nucleophile occurs from both sides)

Non-concerted - has carbocation intermediate

Unimolecular - rate depends on concentration of only the substrate

♦♦♦• Substrate:

Best if tertiary or conjugated (benzylic or allylic) carbocation can be formed as leaving group departs

never primary


♦♦♦• Nucleophile:

Best if more reactive (i.e. more anionic or more basic)

♦♦♦• Leaving Group: Same as SN2

best if more stable (i.e. can support negative charge well)

Examples: TsO- (very good) > I- > Br- > Cl- > F- (poor)

However, tertiary or allylic ROH or ROR' can be reactive under strongly acidic conditions to replace OH or OR

♦♦♦• Solvent:

Same as SN2

Polar Aprotic (i.e. no OH) is best

Examples: dimethylsulfoxide ( CH3 ( HCON(CH3)2 ), acetonitrile ( CH3

Protic solvents (e.g. H2
SOCH3 ), dimethylformamide CN ).
O or ROH) deactivate but can be used in some cases

$<b>____________♦♦☺♦♦____________$

$\sf\purple{By-\:\:\:RAKESH\:\:PATEL}$

$\mathbb{\red{\huge{\:\:\:\:\:THANK\: YOU}}}$
$<b>________▶▶▶⭐⭐⭐◀◀◀________$