Question

racetrack is in the form of a ring whose inner circumference is 352 M and the other circumference is 3396 M find the width of the track

Answer 1

hey mate

Circumference of circle = 2πr

Circumstance of inner ring = 352 meter

2*22/7*r = 352

r = 352*7/2*22

r = 56 meter

Circumference of outer = 3396 meter

2 * 22/7 * r' = 3396

r'= 3396*7/2*22

r' = 540.28 meter ( approx)

Track width = r'-r

width = 540.28-56

hence, Track width = 484.28 meter

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Answer 2

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