Math, asked by Rexlord2318, 9 months ago

Rachel is a stunt driver, and she's escaping from a building that is about to explode! The variable ddd models Rachel's distance from her exit (in meters) ttt seconds after the cameras began recording the stunt. d=-38t+220d=−38t+220d, equals, minus, 38, t, plus, 220 What is Rachel's speed?

Answers

Answered by AditiHegde
61

Given:

The variable d models Rachel's distance from her exit (in meters) t seconds after the cameras began recording the stunt. d = - 38t + 220

To find:

What is Rachel's speed?

Solution:

From given, we have,

The expression that represents the Richel's distance is given by,

d = - 38t + 220

where, d represents the distance in meters

            t represents the time in seconds

We know that, speed = distance by time.

Therefore, we need to differentiate the given equation w.r.t to time to find the speed.

Hence, we have,

d/dt (d) = d/dt [- 38t + 220]

| d/dt (d) | = | - 38 + 0 |

s =  d/dt (d) = 38 m/s

Therefore, the speed of Rachel is 38 m/s.

Answered by gchandracommercial
20

Answer:

Given:

The variable d models Rachel's distance from her exit (in meters) t seconds after the cameras began recording the stunt. d = - 38t + 220

To find:

What is Rachel's speed?

Solution:

From given, we have,

The expression that represents the Richel's distance is given by,

d = - 38t + 220

where, d represents the distance in meters

           t represents the time in seconds

We know that, speed = distance by time.

Therefore, we need to differentiate the given equation w.r.t to time to find the speed.

Hence, we have,

d/dt (d) = d/dt [- 38t + 220]

| d/dt (d) | = | - 38 + 0 |

s =  d/dt (d) = 38 m/s

Therefore, the speed of Rachel is 38 m/s.

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