Question

Racing car has a uniform acceleration
of 4 m/s² what distance
will it cover in
10's after start
​

Answer 1

Answer:

Given:  

Initial velocity is: u=0

Acceleration is: a=4 ms^

Time is: t=10 s

Using second equation of motion:

s=ut+ 1/2at^

s=0×10+1/2×4×10^

 =0+200=200 m

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Explanation:

Answer 2

✬ Distance = 200 m ✬

Explanation:

Given:

• Initial velocity of car is 0 m/s.
• Acceleration of racing car is 4 m/s².
• Time given is 10 seconds.

To Find:

• What distance will it cover in given period of time ?

Formula to be used:

• s = ut + 1/2at²

Solution: By using the second equation of motion.

$\implies{\rm }$ s = ut + 1/2at²

$\implies{\rm }$ s = 0 $\times$ t + 1/2 $\times$ 4 $\times$ 10²

$\implies{\rm }$ s = 0 + 4/2 $\times$ 100

$\implies{\rm }$ s = 4 $\times$ 50

$\implies{\rm }$ s = 200 m

Hence, the car will cover a distance of 200 m.

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★ Know the terms ★

• u = Initial velocity
• v = Final velocity
• t = time
• a = acceleration

➛ Two other laws of motion

• v = u + at ( First law )
• v² = u² + 2as ( Third law )