racing car has a uniform acceleration of 4 metre per second square what distance will it cover in 5 seconds after start
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Answers
Answered by
0
Answer:
The initial velocity = u = 0
The final velocity = v
The acceleration = a and time = t = 10
a = 4
The first equation of motion i.e -v=u+at
v = 0 + 40
v = 40m/s
Thethird equation of motion i.e-2as=v2– u2
2 x 4 x s = 1600
s + 1600/8 = 200m
∴Distance it will cover in 10sec after start is 200m
Answered by
1
Answer:
simply put in
s=ut+at²
s=0*5+½*4*5²
s= 0+50
s= 50m
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